
Physics question…..?
Hi, i need help solving this problem:
Three small children are pulling a rag doll in different directions, each trying to get the doll from the other two. the x-component of the force exerted by the first child is 5.0N, and the y-component is 3.0N. The second child’s force is -4.0 in the x-direction and 2.0N in y-direction. The x and y components of the third force are 1.0N and -8.0N. what are the components of the net force acting on the rag doll? What is the direction and magnitude of the net force?
//I tried and got this: x-component: 2N and y-component: -3N Resultant vector: 3.605N at -33.60 above x-direction (or 3.605N X-33.6Y)..is this correct? if not, what’s the correct answer? How do you get it if possible to show..
thanks
@Kraig, how do you figure the angles? How did you know the angles were sin,cosin etc? I am confused
This is how I would set up the equation.
1st child: X=5cos0 Y=3sin90
2nd child: X=-4cos180 Y=2sin90
3rd child: X=1cos0 Y=-8sin270
Fx= 5+4+1
Fx= 10
Fy=3+2+8
Fy= 13
Fnet = C(squared) = Fx(squared) + Fy(squared)
Fnet = C(sq’d) = 100 + 169
Fnet = C(sq’d) = 269
Fnet = Square root of 269
Fnet = 16.40N (rounded off to 2 decimal places)
Angle = Tan-1(Fy/Fx)
Angle = Tan-1(13/10)
Angle = 52 degrees (Rounded off)
Answer = 16.4N(East52*North) or 16.4(North48*East)
OR!!
Answer = 16.4N(X52*Y) or 16.4N(Y48*E)
Hopefully my calculations are correct.

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